Jefferson, Ohio

Jefferson is a village in Ashtabula County, Ohio, United States. The population was 3,226 at the 2020 census.^[3] It is the county seat of Ashtabula County.^[5]

Jefferson, Ohio
Village
Ashtabula County Courthouse
Location of Jefferson, Ohio
Location of Jefferson in Ashtabula County
Coordinates: 41°44′19″N 80°45′25″W
Country	United States
State	Ohio
County	Ashtabula
Area [1]
• Total	2.54 sq mi (6.57 km2)
• Land	2.54 sq mi (6.57 km2)
• Water	0.00 sq mi (0.00 km2)
Elevation [2]	961 ft (293 m)
Population  (2020)[3]
• Total	3,226
• Density	1,271.58/sq mi (491.04/km2)
Time zone	UTC-5 (Eastern (EST))
• Summer (DST)	UTC-4 (EDT)
ZIP code	44047
Area code	440
FIPS code	39-38500[4]
GNIS feature ID	1042061[2]
Website	https://jeffersonohio.gov/

References

1. "ArcGIS REST Services Directory". United States Census Bureau. Retrieved September 20, 2022.
2. U.S. Geological Survey Geographic Names Information System: Jefferson, Ohio
3. "Profile of General Population and Housing Characteristics: 2020 Demographic Profile Data (DP-1): Jefferson village, Ohio". United States Census Bureau. Retrieved March 16, 2024.
4. "U.S. Census website". United States Census Bureau. Retrieved January 31, 2008.
5. National Association of Counties. "NACo County Explorer". Retrieved March 15, 2024.