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City in Gujarat, India From Wikipedia, the free encyclopedia
Kheralu is a city and a municipality in Mehsana district in the Indian state of Gujarat. It is a little north of Mahesana Proper town and it is approximately half the size of Mehsana.
Kheralu | |
---|---|
city | |
Coordinates: 23.88°N 72.62°E | |
Country | India |
State | Gujarat |
District | Mehsana |
Elevation | 149 m (489 ft) |
Population (2001) | |
• Total | 20,143 |
Languages | |
• Official | Gujarati, Hindi, English |
Time zone | UTC+5:30 (IST) |
Vehicle registration | GJ 02 |
Website | gujaratindia |
A Bodhisattva sculpture from 3rd-4th century CE was discovered in Kheralu.[1]
Kheralu was home for a community of Humbada Jains in the 15th-16th century CE.[2]
Kheralu is located at 23.88°N 72.62°E.[3] It has an average elevation of 149 metres (488 feet). It is the second largest town in its district after Mehsana proper town.[citation needed]
The river Rupen flows through the taluka of Kheralu. Originating from the hills of Taranga in Kheralu, it eventually flows into the Little Rann of Kutch.[4][5]
As of 2001[update] India census,[6] Kheralu had a population of 20,143. Males constitute 52% of the population and females 48%. Kheralu has an average literacy rate of 68%, higher than the national average of 59.5%: male literacy is 76%, and female literacy is 59%. In Kheralu, 13% of the population is under 6 years of age.
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