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2019 tennis event results From Wikipedia, the free encyclopedia
Evan King and Hunter Reese were the defending champions[1] but only Reese chose to defend his title, partnering André Göransson. Reese lost in the first round to Treat Huey and Fabrice Martin.
Doubles | |
---|---|
2019 Sarasota Open | |
Champions | Martín Cuevas Paolo Lorenzi |
Runners-up | Luke Bambridge Jonny O'Mara |
Score | 7–6(7–5), 7–6(8–6) |
Martín Cuevas and Paolo Lorenzi won the title after defeating Luke Bambridge and Jonny O'Mara 7–6(7–5), 7–6(8–6) in the final.
First round | Quarterfinals | Semifinals | Final | ||||||||||||||||||||||||
1 | L Bambridge J O'Mara | 6 | 3 | [10] | |||||||||||||||||||||||
T Sandgren J Ward | 2 | 6 | [6] | 1 | L Bambridge J O'Mara | 6 | 6 | ||||||||||||||||||||
A Lawson P Polansky | 77 | 6 | A Lawson P Polansky | 3 | 3 | ||||||||||||||||||||||
ITF | S Ehrat A Zhurbin | 62 | 2 | 1 | L Bambridge J O'Mara | 6 | 6 | ||||||||||||||||||||
3 | N Lammons A-u-H Qureshi | 77 | 6 | 3 | N Lammons A-u-H Qureshi | 4 | 2 | ||||||||||||||||||||
WC | JC Aragone M Giron | 65 | 4 | 3 | N Lammons A-u-H Qureshi | 64 | 6 | [10] | |||||||||||||||||||
A Göransson H Reese | 6 | 3 | [5] | PR | T Huey F Martin | 77 | 4 | [8] | |||||||||||||||||||
PR | T Huey F Martin | 4 | 6 | [10] | 1 | L Bambridge J O'Mara | 65 | 66 | |||||||||||||||||||
H Heliövaara H Laaksonen | M Cuevas P Lorenzi | 77 | 78 | ||||||||||||||||||||||||
M Cuevas P Lorenzi | w/o | M Cuevas P Lorenzi | 65 | 7 | [10] | ||||||||||||||||||||||
ITF | A Rinderknech D Yevseyev | 62 | 77 | [7] | 4 | R Maytín F Romboli | 77 | 5 | [7] | ||||||||||||||||||
4 | R Maytín F Romboli | 77 | 63 | [10] | M Cuevas P Lorenzi | 6 | 77 | ||||||||||||||||||||
M Krueger M Reid | 7 | 77 | WC | B Arias S Bangoura | 4 | 63 | |||||||||||||||||||||
WC | Russell Berdusco Micah Braswell | 5 | 62 | M Krueger M Reid | 4 | 4 | |||||||||||||||||||||
WC | B Arias S Bangoura | 5 | 7 | [10] | WC | B Arias S Bangoura | 6 | 6 | |||||||||||||||||||
2 | J Nedunchezhiyan P Raja | 7 | 5 | [5] |
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