2018 Bengaluru Open – Doubles

Mikhail Elgin and Divij Sharan were the defending champions but chose not to defend their title.

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Britons Max Purcell and Luke Saville won the title after defeating Purav Raja and Antonio Šančić 7–6^(7–3), 6–3 in the final.

First round					Quarterfinals					Semifinals					Final

1	K Krawietz J Nedunchezhiyan	3	6	[7]
	A Martin H Podlipnik Castillo	6	3	[10]		A Martin H Podlipnik Castillo	6	2	[2]
	C-p Hsieh T-h Yang	6	3	[10]		C-p Hsieh T-h Yang	4	6	[10]
	A Nedovyesov M Trungelliti	1	6	[3]							C-p Hsieh T-h Yang	3	4
3	S Balaji V Vardhan	6	6								M Purcell L Saville	6	6
WC	S Nagal B Schnur	4	3		3	S Balaji V Vardhan	6³	3
WC	C Sood L Sood	2	2			M Purcell L Saville	7⁷	6
	M Purcell L Saville	6	6													M Purcell L Saville	7⁷	6
WC	SDP Dev N Kaliyanda Poonacha	1	7⁷	[10]											2	P Raja A Šančić	6³	3
	A Pavlioutchenkov F Peliwo	6	6³	[2]	WC	SDP Dev N Kaliyanda Poonacha	3	6⁵
	A Kadhe S Myneni	6	3	[11]		A Kadhe S Myneni	6	7⁷
4	Sa Ratiwatana So Ratiwatana	3	6	[9]							A Kadhe S Myneni	6	2	[8]
	R Albot M Polmans	4	5							2	P Raja A Šančić	3	6	[10]
	B Kavčič T-S Weissborn	6	7			B Kavčič T-S Weissborn
	R Arneodo Q Halys	4	7⁸	[9]	2	P Raja A Šančić	w/o
2	P Raja A Šančić	6	6⁶	[11]

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