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1888 United States presidential election in Maryland

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1888 United States presidential election in Maryland
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The 1888 United States presidential election in Maryland took place on November 6, 1888, as part of the 1888 United States presidential election. Voters chose eight representatives, or electors to the Electoral College, who voted for president and vice president.

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Maryland voted for the Democratic nominee, incumbent President Grover Cleveland, over the Republican nominee, Benjamin Harrison. Cleveland won the state by a narrow margin of 2.94%. Despite the narrow margin, Maryland was still 2.11% more Democratic than the nation at large.[1]

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Results

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Results by county

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Counties that flipped from Democratic to Republican

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