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Ruso, North Dakota
City in North Dakota, United States / From Wikipedia, the free encyclopedia
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Ruso is a city in McLean County, North Dakota, in the USA. The population was 1 at the 2020 census,[3] making Ruso the least populous incorporated place in North Dakota. [5] It is tied with Monowi, Nebraska at being the least populated community in the United States that is currently inhabited.
Quick Facts Country, State ...
Ruso, North Dakota | |
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![]() Location in Ruso. | |
Coordinates: 47°50′14″N 100°56′03″W | |
Country | United States |
State | North Dakota |
County | McLean |
Founded | July 17, 1906 |
Incorporated | July 7, 1909 |
Area | |
• Total | 0.25 sq mi (0.64 km2) |
• Land | 0.25 sq mi (0.64 km2) |
• Water | 0.00 sq mi (0.00 km2) |
Elevation | 2,074 ft (632 m) |
Population | |
• Total | 1 |
• Estimate (2023)[4] | 5 |
• Density | 4.02/sq mi (1.55/km2) |
Time zone | UTC–6 (Central (CST)) |
• Summer (DST) | UTC–5 (CDT) |
ZIP Code | 58778 |
Area code | 701 |
FIPS code | 38-69140 |
GNIS feature ID | 1036247[2] |
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