county seat of Pike County, Indiana, United States From Wikipedia, the free encyclopedia
Petersburg, Indiana is a city in Indiana in the United States. It is the county seat of Pike County.
Petersburg, Indiana | |
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![]() | |
![]() Location of Petersburg in Pike County, Indiana. | |
Coordinates: 38°29′30″N 87°16′49″W | |
Country | United States |
State | Indiana |
County | Pike |
Township | Washington |
Area | |
• Total | 1.47 sq mi (3.81 km2) |
• Land | 1.47 sq mi (3.80 km2) |
• Water | 0.00 sq mi (0.00 km2) 0% |
Elevation | 482 ft (147 m) |
Population | |
• Total | 2,304 |
• Density | 1,569.48/sq mi (605.91/km2) |
Time zone | UTC-5 (EST) |
• Summer (DST) | UTC-4 (EDT) |
ZIP code | 47567 |
Area code | 812 |
FIPS code | 18-59364[4] |
GNIS feature ID | 449709 |
Interstate Highways | ![]() |
Major State Roads | ![]() ![]() ![]() ![]() |
Website | http://www.petersburg.in.gov/ |
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