Sand Creek Township, Jennings County, Indiana
Township in Indiana, United States From Wikipedia, the free encyclopedia
Sand Creek Township is one of eleven townships in Jennings County, Indiana, United States. As of the 2020 census, its population was 859 (down from 872 at 2010[1]) and it contained 364 housing units.[2]
Sand Creek Township | |
|---|---|
 Location in Jennings County | |
| Coordinates: 39°05′16″N 85°36′25″W | |
| Country | United States |
| State | Indiana |
| County | Jennings |
| Government | |
| • Type | Indiana township |
| Area | |
• Total | 27.95 sq mi (72.4 km2) |
| • Land | 27.72 sq mi (71.8 km2) |
| • Water | 0.23 sq mi (0.6 km2) 0.82% |
| Elevation | 725 ft (221 m) |
| Population (2020) | |
• Total | 859 |
| • Density | 31/sq mi (12/km2) |
| GNIS feature ID | 0453833 |
Geography
According to the 2010 census, the township has a total area of 27.95 square miles (72.4 km2), of which 27.72 square miles (71.8 km2) (or 99.18%) is land and 0.23 square miles (0.60 km2) (or 0.82%) is water.[1] The streams of Bear Creek, Fish Creek, Ice Creek, Millstone Creek, Poplar Root Creek and Rock Creek run through this township.
Unincorporated towns
Adjacent townships
- Jackson Township, Decatur County (north)
- Sand Creek Township, Decatur County (north)
- Columbia Township (east)
- Campbell Township (southeast)
- Center Township (south)
- Geneva Township (west)
Cemeteries
The township contains three cemeteries: Bear Creek, Day and Fish Creek.
Major highways
References
External links
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