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Protactinium(V) iodide is an inorganic compound, with the chemical formula of PaI5.
| Identifiers | |
|---|---|
| Properties | |
| I5Pa | |
| Molar mass | 865.55823 g·mol−1 |
| Appearance | black needle crystals[1] |
| Related compounds | |
Other anions |
Protactinium(V) fluoride Protactinium(V) chloride Protactinium(V) bromide |
Other cations |
Praseodymium(III) iodide Thorium(IV) iodide Uranium(IV) iodide |
Except where otherwise noted, data are given for materials in their standard state (at 25 °C [77 °F], 100 kPa).
| |
It can be prepared by the reaction of metals protactinium and iodine, or by reacting protactinium(V) chloride, protactinium(V) bromide or protactinium(V) oxide with silicon tetraiodide.[2]
It reacts with antimony trioxide in a vacuum at 150 °C to give the iodide oxides PaOI3 and PaO2I; it reacts with protactinium(V) bromide at 350 °C to obtain mixed halides PaBr3I2.[2] It reacts with the monocarbide at 600 °C to give tetraiodide.[3]
Aristid von Grosse was able to produce pure metallic protactinium with the decomposition of protactinium(V) iodide.[4][5]
When heated at 300 °C for a long time, it decomposes and iodine is released:[1]
- PaI5 → PaI3 + I2
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