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Township in Indiana, United States From Wikipedia, the free encyclopedia
Oak Grove Township is one of eleven townships in Benton County, Indiana. As of the 2020 census, its population was 1,551 and it contained 690 housing units.[3] It was one of the first three townships originally created by the county's commissioners in 1840.[4] It takes its name from White Oak Grove which grew southwest of Oxford.[5]
Oak Grove Township | |
|---|---|
 Location of Oak Grove Township in Benton County | |
| Coordinates: 40°31′09″N 87°15′54″W | |
| Country | United States |
| State | Indiana |
| County | Benton |
| Organized | July 1840 |
| Government | |
| • Type | Indiana township |
| Area | |
| • Total | 35.53 sq mi (92.0 km2) |
| • Land | 35.51 sq mi (92.0 km2) |
| • Water | 0.02 sq mi (0.05 km2) |
| Elevation | 748 ft (228 m) |
| Population (2020) | |
| • Total | 1,551 |
| • Density | 43.6/sq mi (16.8/km2) |
| Time zone | UTC-5 (EST) |
| • Summer (DST) | UTC-4 (EDT) |
| FIPS code | 18-55620[2] |
| GNIS feature ID | 453681 |
According to the 2020 census, the township has a total area of 35.53 square miles (92.0 km2), of which 35.51 square miles (92.0 km2) (or 99.94%) is land and 0.02 square miles (0.052 km2) (or 0.06%) is water.[3]
The township contains two cemeteries: Justus and Oxford.
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