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In the mathematical field of linear algebra and convex analysis, the numerical range or field of values of a complex matrix A is the set
where denotes the conjugate transpose of the vector . The numerical range includes, in particular, the diagonal entries of the matrix (obtained by choosing x equal to the unit vectors along the coordinate axes) and the eigenvalues of the matrix (obtained by choosing x equal to the eigenvectors).
In engineering, numerical ranges are used as a rough estimate of eigenvalues of A. Recently, generalizations of the numerical range are used to study quantum computing.
A related concept is the numerical radius, which is the largest absolute value of the numbers in the numerical range, i.e.
Let sum of sets denote a sumset.
General properties
Numerical radius
Most of the claims are obvious. Some are not.
If is Hermitian, then it is normal, so it is the convex hull of its eigenvalues, which are all real.
Conversely, assume is on the real line. Decompose , where is a Hermitian matrix, and an anti-Hermitian matrix. Since is on the imaginary line, if , then would stray from the real line. Thus , and is Hermitian.
The elements of are of the form , where is projection from to a one-dimensional subspace.
The space of all one-dimensional subspaces of is , which is a 2-sphere. The image of a 2-sphere under a linear projection is a filled ellipse.
In more detail, such are of the form where , satisfying , is a point on the unit 2-sphere.
Therefore, the elements of , regarded as elements of is the composition of two real linear maps and , which maps the 2-sphere to a filled ellipse.
is the image of a continuous map from the closed unit sphere, so it is compact.
For any of unit norm, project to the span of as . Then is a filled ellipse by the previous result, and so for any , let , we have
Let satisfy these properties. Let be the original numerical range.
Fix some matrix . We show that the supporting planes of and are identical. This would then imply that since they are both convex and compact.
By property (4), is nonempty. Let be a point on the boundary of , then we can translate and rotate the complex plane so that the point translates to the origin, and the region falls entirely within . That is, for some , the set lies entirely within , while for any , the set does not lie entirely in .
The two properties of then imply that and that inequality is sharp, meaning that has a zero eigenvalue. This is a complete characterization of the supporting planes of .
The same argument applies to , so they have the same supporting planes.
For (2), if is normal, then it has a full eigenbasis, so it reduces to (1).
Since is normal, by the spectral theorem, there exists a unitary matrix such that , where is a diagonal matrix containing the eigenvalues of .
Let . Using the linearity of the inner product, that , and that are orthonormal, we have:
By affineness of , we can translate and rotate the complex plane, so that we reduce to the case where has a sharp point at , and that the two supporting planes at that point both make an angle with the imaginary axis, such that since the point is sharp.
Since , there exists a unit vector such that .
By general property (4), the numerical range lies in the sectors defined by: At , the directional derivative in any direction must vanish to maintain non-negativity. Specifically:
Expanding this derivative:
Since the above holds for all , we must have:
For any and , substitute into the equation: Choose and , then simplify, we obtain for all , thus .
Let . We have .
By Cauchy–Schwarz,
For the other one, let , where are Hermitian.
Since is on the real line, and is on the imaginary line, the extremal points of appear in , shifted, thus both .
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