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American tennis player From Wikipedia, the free encyclopedia
Elizabeth Galphin (born August 26, 1968) is an American former professional tennis player.
Country (sports) | United States |
---|---|
Born | August 26, 1968 |
Prize money | $50,062 |
Singles | |
Highest ranking | No. 185 (May 9, 1988) |
Grand Slam singles results | |
Australian Open | 2R (1988) |
French Open | Q2 (1988) |
Wimbledon | Q1 (1988) |
Doubles | |
Highest ranking | No. 225 (Apr 25, 1988) |
Grand Slam doubles results | |
Australian Open | 1R (1988, 1989) |
Wimbledon | Q3 (1988) |
Galphin, ranked as high as 185 in the world, had a third round appearance at the 1987 Argentine Open, beating seeded player Christiane Jolissaint en route. She featured in the singles main draw of the 1988 Australian Open and won her first round match against Paula Smith.[1] Her son Milledge Cossu is a tennis player, currently for Purdue University.[2]
Result | No. | Date | Tournament | Surface | Opponent | Score |
---|---|---|---|---|---|---|
Loss | 1. | May 1987 | Bath, United Kingdom | Clay | María José Llorca | 1–6, 6–3, 1–6 |
Loss | 2. | Jul 1987 | Spartanburg, United States | Clay | Ingelise Driehuis | 2–6, 4–6 |
Result | No. | Date | Tournament | Surface | Partner | Opponents | Score |
---|---|---|---|---|---|---|---|
Loss | 1. | Nov 1989 | Pforzheim, West Germany | Hard | Caroline Schneider | Elena Bryukhovets Eugenia Maniokova |
1–6, 1–6 |
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