Dudley Township, Ohio
Township in Ohio, United States From Wikipedia, the free encyclopedia
Township in Ohio, United States From Wikipedia, the free encyclopedia
Dudley Township is one of the fifteen townships of Hardin County, Ohio, United States. As of the 2020 census the population was 1,490.
Dudley Township, Hardin County, Ohio | |
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Coordinates: 40°35′38″N 83°29′3″W | |
Country | United States |
State | Ohio |
County | Hardin |
Area | |
• Total | 37.37 sq mi (96.78 km2) |
• Land | 37.36 sq mi (96.75 km2) |
• Water | 0.02 sq mi (0.04 km2) |
Elevation | 948 ft (289 m) |
Population | |
• Total | 1,490 |
• Density | 40/sq mi (15/km2) |
Time zone | UTC-5 (Eastern (EST)) |
• Summer (DST) | UTC-4 (EDT) |
FIPS code | 39-22736[3] |
GNIS feature ID | 1086259[1] |
Located in the southeastern part of the county, it borders the following townships:
No municipalities are located in Dudley Township, although the unincorporated community of Hepburn lies in the township's north.
Dudley Township was established in the 1830s, and named for Moses Dudley, a pioneer settler.[4] It is the only Dudley Township statewide.[5]
The township is governed by a three-member board of trustees, who are elected in November of odd-numbered years to a four-year term beginning on the following January 1. Two are elected in the year after the presidential election and one is elected in the year before it. There is also an elected township fiscal officer,[6] who serves a four-year term beginning on April 1 of the year after the election, which is held in November of the year before the presidential election. Vacancies in the fiscal officership or on the board of trustees are filled by the remaining trustees.
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