Dubrava, Zagreb County
Municipality in Croatia From Wikipedia, the free encyclopedia
Dubrava is a village and a municipality ("općina") in Zagreb County, Croatia.
Dubrava | |
|---|---|
| Municipality of Dubrava | |
 | |
 | |
 Dubrava Location of Dubrava in Croatia | |
| Coordinates: 45°49′48″N 16°30′36″E | |
| Country | Croatia |
| County | Zagreb County |
| Area | |
| 115.7 km2 (44.7 sq mi) | |
| • Urban | 8.0 km2 (3.1 sq mi) |
| Population (2021)[2] | |
| 4,520 | |
| • Density | 39/km2 (100/sq mi) |
| • Urban | 1,233 |
| • Urban density | 150/km2 (400/sq mi) |
| Time zone | UTC+1 (Central European Time) |
| Vehicle registration | ZG |
| Website | opcina-dubrava |
According to the 2001 Croatian census, there are 5,478 inhabitants in the municipality, 94% which are Croats.[3] They live in 27 naselja:
- Bađinec - 173
- Brezje - 121
- Donji Marinkovac - 101
- Donji Vukšinac - 103
- Dubrava - 1,275
- Dubravski Markovac - 169
- Gornji Marinkovac - 157
- Gornji Vukšinac - 146
- Graberec - 226
- Habjanovac - 200
- Koritna - 204
- Kostanj - 102
- Kunđevac - 92
- Ladina - 125
- Mostari - 211
- Nova Kapela - 279
- Novaki - 232
- Paruževac - 157
- Pehardovac - 16
- Podlužan - 185
- Radulec - 132
- Stara Kapela - 242
- Svinjarec - 63
- Zetkan - 209
- Zgališće - 180
- Zvekovac - 217
- Žukovec - 161
The total area of Dubrava is 4.41 square kilometers (1.70 sq mi).[4]
References
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