Bucyrus Township, Ohio
Township in Ohio, United States From Wikipedia, the free encyclopedia
Township in Ohio, United States From Wikipedia, the free encyclopedia
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Bucyrus Township is one of the sixteen townships of Crawford County, Ohio, United States. As of the 2020 census the population was 821.
Bucyrus Township, Ohio | |
---|---|
Coordinates: 40°47′6″N 83°0′34″W | |
Country | United States |
State | Ohio |
County | Crawford |
Area | |
• Total | 31.4 sq mi (81.3 km2) |
• Land | 31.3 sq mi (81.1 km2) |
• Water | 0.08 sq mi (0.2 km2) |
Elevation | 991 ft (302 m) |
Population | |
• Total | 821 |
• Density | 26/sq mi (10/km2) |
Time zone | UTC-5 (Eastern (EST)) |
• Summer (DST) | UTC-4 (EDT) |
ZIP code | 44820 |
Area code | 419 |
FIPS code | 39-10044[3] |
GNIS feature ID | 1085933[1] |
Located in the southwestern part of the county, it borders the following townships:
Most of the city of Bucyrus, the county seat of Crawford County, is located in northeastern Bucyrus Township.
It is the only Bucyrus Township statewide.
The township is governed by a three-member board of trustees, who are elected in November of odd-numbered years to a four-year term beginning on the following January 1. Two are elected in the year after the presidential election and one is elected in the year before it. There is also an elected township fiscal officer,[4] who serves a four-year term beginning on April 1 of the year after the election, which is held in November of the year before the presidential election. Vacancies in the fiscal officership or on the board of trustees are filled by the remaining trustees.