Battle of Bantam

The naval Battle of Bantam took place on 27 December 1601 in Bantam Bay (now Banten Bay), Indonesia, when an exploration fleet of five Dutch ships under the command of Wolfert Harmensz and a Portuguese fleet under André Furtado de Mendonça, sent from Goa to restore Portuguese authority, met in the Indonesian archipelago. The battle resulted in Dutch victory and forced the Portuguese to retreat.^[1] The outnumbered Dutch fleet took three Portuguese fustas as prizes.

Battle of Bantam
Part of Dutch-Portuguese War
Victory of the Dutch over the Portuguese fleet in Banten, 1601.
Date 27 December 1601 Location Banten Bay, Indonesia Result Dutch victory
Belligerents
Dutch Republic	Portuguese Empire
Strength
5 ships	8 galleons several fustas
Casualties and losses
None	3 fustas captured

Ships involved

• Netherlands
  • Gelderland (Wolfert Harmensz)
  • Zeelandia (Jan Cornelisz)
  • Utrecht (Jan Martensz)
  • Wachter (yacht) (Gerrit Hendricksz Roobol)
  • Duyfken (yacht) (Willem Schouten)
• Portugal (André Furtado de Mendonça), 30 vessels total
  • 8 galleons
  • Several fustas—3 set alight and captured by Dutch