2018 Brownlow Medal
Award From Wikipedia, the free encyclopedia
The 2018 Brownlow Medal was the 91st year the award was presented to the player adjudged the fairest and best player during the Australian Football League (AFL) home-and-away season.[1] Tom Mitchell of the Hawthorn Football Club won the medal with 28 votes.
| 2018 Brownlow Medal | |
|---|---|
2018 Brownlow Medalist, Tom Mitchell | |
| Date | 24 September |
| Location | Crown Palladium |
| Hosted by | Bruce McAvaney |
| Winner | Tom Mitchell (Hawthorn) (28 votes) |
| Television/radio coverage | |
| Network | Seven Network Telstra |
Leading vote-getters
| Player | Votes | |
|---|---|---|
| 1st | Tom Mitchell (Hawthorn) | 28 |
| 2nd | Steele Sidebottom (Collingwood) | 24 |
| 3rd | Angus Brayshaw (Melbourne) | 21 |
| =4th | Patrick Cripps (Carlton) | 20 |
| Max Gawn (Melbourne) | ||
| =6th | Rory Laird (Adelaide) | 19 |
| Dustin Martin (Richmond) | ||
| =8th | Jack Steven (St Kilda) | 18 |
| Dayne Beams (Brisbane Lions) | ||
| =10th | Brodie Grundy (Collingwood) | 17 |
| Patrick Dangerfield (Geelong) |
Voting procedure
The three field umpires (those umpires who control the flow of the game, as opposed to goal or boundary umpires) confer after each match and award three votes, two votes, and one vote to the players they regard as the best, second-best and third-best in the match, respectively. The votes are kept secret until the awards night, and they are read and tallied on the evening.[2]
References
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