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2005 BCR Open Romania – Doubles

2005 tennis event results From Wikipedia, the free encyclopedia

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Lucas Arnold Ker and Mariano Hood were the defending champions, but Arnold Ker did not compete this year. Hood teamed up with Martín García and lost in the quarterfinals to Juan Ignacio Chela and Luis Horna.

Quick Facts Doubles, Final ...

José Acasuso and Sebastián Prieto won the title by defeating Victor Hănescu and Andrei Pavel 6–3, 4–6, 6–3 in the final.[1]

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Seeds

Draw

Key

Draw

First round Quarterfinals Semifinals Final
1 Argentina M García
Argentina M Hood
6 56 6
WC Romania V Ioniță
Romania R Sabău
1 68 2 1 Argentina M García
Argentina M Hood
3 3
Argentina JI Chela
Peru L Horna
6 6 Argentina JI Chela
Peru L Horna
6 6
Germany T Behrend
Germany A Waske
2 2 Argentina JI Chela
Peru L Horna
3 4
3 Argentina J Acasuso
Argentina S Prieto
6 6 3 Argentina J Acasuso
Argentina S Prieto
6 6
South Africa J Coetzee
South Africa C Haggard
4 4 3 Argentina J Acasuso
Argentina S Prieto
6 6
Germany F Mayer
Netherlands R Wassen
6 67 Germany F Mayer
Netherlands R Wassen
1 2
France PH Mathieu
Belgium R Rochus
4 51 3 Argentina J Acasuso
Argentina S Prieto
6 4 6
Romania V Hănescu
Romania A Pavel
6 67 Romania V Hănescu
Romania A Pavel
3 6 3
Czech Republic P Pála
Czech Republic D Škoch
4 53 Romania V Hănescu
Romania A Pavel
6 67
Spain N Almagro
Spain A Martín
2 2 4 Poland M Fyrstenberg
Poland M Matkowski
2 53
4 Poland M Fyrstenberg
Poland M Matkowski
6 6 Romania V Hănescu
Romania A Pavel
6 6
WC Romania I Moldovan
Romania G Moraru
6 6 WC Romania I Moldovan
Romania G Moraru
4 4
Argentina C Berlocq
Argentina M Puerta
1 2 WC Romania I Moldovan
Romania G Moraru
610 6
Italy D Sanguinetti
Belgium T Vanhoudt
6 67 Italy D Sanguinetti
Belgium T Vanhoudt
58 4
2 Austria J Knowle
Germany M Kohlmann
4 50
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References

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