1969 CONCACAF Championship qualification

Main article: 1969 CONCACAF Championship

A total of 9 CONCACAF teams entered the competition,^[1] eventually reduced to 8 after Haiti renounced.^[2] Later on, Haiti tried to join again but the late application was rejected.^[3] Honduras, El Salvador and the USA^[4] did not enter.
Costa Rica (as the hosts), Guatemala (as the defending champions), the Netherlands Antilles and Trinidad and Tobago qualified automatically. Play-offs were arranged for the remaining two spots.^[5]

Preliminary round

Series One

Mexico	3–0	Bermuda
Mancilla 6', 30' Langarica 52'

21 October 1969

Estadio Azteca, Mexico City, Mexico

Bermuda	2–1	Mexico
Brangman 34' Dowling 61'		Santana 56'

2 November 1969

Bermuda National Stadium, Hamilton, Bermuda

Mexico qualifies with aggregate score of 4-2.

Series Two

Jamaica	1–1	Panama
Ziadie (pen.)		Tapia 46'

3 November 1969

Independence Park, Kingston, Jamaica

Panama	1–2	Jamaica
Espinoza 20'		Largie 27' Hill 85'

5 November 1969

Independence Park, Kingston, Jamaica^[6]

Jamaica qualifies with aggregate score of 3-2.

Teams qualified to the 1969 CONCACAF Championship

•  Mexico (Series one winners)
•  Jamaica (Series two winners)