1940 United States Senate election in Indiana

For related races, see 1940 United States Senate elections.

The 1940 United States Senate election in Indiana took place on November 5, 1940. Incumbent Democratic U.S. Senator Sherman Minton ran for re-election to a second term, but lost narrowly to Republican Raymond E. Willis.

1940 United States Senate election in Indiana

← 1934 November 5, 1940 1946 →

Nominee Raymond E. Willis Sherman Minton Party Republican Democratic Popular vote 888,070 864,803 Percentage 50.45% 49.13%

County results Willis:      50–60%      60–70% Minton:      40–50%      50–60%      60–70%

U.S. senator before election Sherman Minton Democratic Elected U.S. Senator Raymond E. Willis Republican

General election

Candidates

• John H. Kingsbury (Socialist)
• Sherman Minton, incumbent Senator since 1935 (Democratic)
• Carl W. Thompson (Prohibition)
• Raymond E. Willis, former State Representative from Angola and nominee for Senate in 1938 (Republican)

Results

1940 U.S. Senate election in Indiana^[1][2]

Party		Candidate	Votes	%	±%
	Republican	Raymond E. Willis	888,070	50.45%	2.97
	Democratic	Sherman Minton (incumbent)	864,803	49.13%	2.33
	Prohibition	Carl W. Thompson	5,621	0.32%	0.02
	Socialist	John H. Kingsbury	1,751	0.10%	0.54
Total votes			1,760,245	100.00%
	Republican gain from Democratic

See also

• 1940 United States Senate elections

References

1. Clerk of the U.S. House of Representatives (1941). "Statistics of the Presidential and Congressional Election of November 5, 1940" (PDF). U.S. Government Printing Office.
2. "Our Campaigns – IN US Senate Race – Nov 05, 1940". www.ourcampaigns.com.