1916 United States presidential election in Delaware

The 1916 United States presidential election in Delaware took place on November 7, 1916. All 48 contemporary states participated in the 1916 United States presidential election. Voters chose three electors to the Electoral College, which selected the president and vice president.

Main article: 1916 United States presidential election

1916 United States presidential election in Delaware

← 1912 November 7, 1916 1920 →

Nominee Charles Evans Hughes Woodrow Wilson Party Republican Democratic Home state New York New Jersey Running mate Charles W. Fairbanks Thomas R. Marshall Electoral vote 3 0 Popular vote 26,011 24,753 Percentage 50.20% 47.78%

County Results Hughes   50-60% Wilson   50-60%

President before election Woodrow Wilson Democratic Elected President Woodrow Wilson Democratic

Republican nominee and Supreme Court justice Charles Evans Hughes carried Delaware with 50.20% of the vote, defeating Democratic nominee and incumbent president Woodrow Wilson, who won 47.78% of the vote. This election marks one of three times in the 20th century that the state voted for the losing candidate, along with 1932 and 1948.

Wilson was the first Democrat to win the presidency without Delaware since James K. Polk in 1844, and Hughes the first Republican to ever carry Delaware without winning the presidency.

Results

1916 United States presidential election in Delaware[1]
Party		Candidate	Votes	Percentage	Electoral votes
	Republican	Charles Evans Hughes	26,011	50.20%	3
	Democratic	Woodrow Wilson (inc.)	24,753	47.78%	0
	Prohibition	Frank Hanly	566	1.09%	0
	Socialist	Allan L. Benson	480	0.93%	0
Totals			51,810	100.0%	3

See also

• United States presidential elections in Delaware

References

1. "1916 Presidential General Election Results - Delaware". Dave Leip's Atlas of U.S. Presidential Elections. Retrieved November 22, 2020.