1916 United States Senate election in Wyoming

The 1916 United States Senate election in Wyoming took place on November 7, 1916. Incumbent senator Clarence D. Clark, a Republican, sought re-election in his first popular election. He was opposed by John B. Kendrick, the incumbent governor of Wyoming and the Democratic nominee. Owing in part to President Woodrow Wilson's strong performance in the presidential election that year, Kendrick won a narrow but decisive victory over Clark, winning the first of three terms in the U.S. Senate.

1916 United States Senate election in Wyoming

← 1911 November 7, 1916 1922 →

Nominee John B. Kendrick Clarence D. Clark Party Democratic Republican Popular vote 26,324 23,258 Percentage 51.47% 45.47%

County results Kendrick:      40–50%      50–60% Clark:      40–50%      50–60%

U.S. senator before election Clarence D. Clark Republican Elected U.S. Senator John B. Kendrick Democratic

Democratic primary

Candidates

• John B. Kendrick, Governor of Wyoming

Results

Democratic primary^[1]

Party		Candidate	Votes	%
	Democratic	John B. Kendrick	2,877	100.00%
Total votes			2,877	100.00%

Republican primary

Candidates

• Clarence D. Clark, incumbent U.S. Senator

Results

Republican primary^[1]

Party		Candidate	Votes	%
	Republican	Clarence D. Clark (inc.)	14,045	100.00%
Total votes			14,045	100.00%

General election

Results

1916 United States Senate election in Wyoming^[1]

Party		Candidate	Votes	%
	Democratic	John B. Kendrick	26,324	51.47%
	Republican	Clarence D. Clark (inc.)	23,258	45.47%
	Socialist	Paul L. Paulsen	1,334	2.61%
	Progressive	Arthur B. Campbell	231	0.45%
Total votes			51,147	100.00%
	Democratic gain from Republican

References

1. Erwin, Marie (1974). Trenholm, Virginia Cole (ed.). Wyoming Blue Book (PDF). Vol. 2. Cheyenne, Wyo.: Pioneer Printing & Stationery Co. pp. 589–90.