1894 Rhode Island gubernatorial election

The 1894 Rhode Island gubernatorial election was held on April 4, 1894. Incumbent Republican Daniel Russell Brown defeated Democratic nominee David S. Baker with 53.15% of the vote.

1894 Rhode Island gubernatorial election

← 1893 April 4, 1894 1895 →

Nominee Daniel Russell Brown David S. Baker Party Republican Democratic Popular vote 29,157 22,650 Percentage 53.15% 41.29%

County results Brown:      50–60%      60–70%

Governor before election Daniel Russell Brown Republican Elected Governor Daniel Russell Brown Republican

General election

Candidates

Major party candidates

• Daniel Russell Brown, Republican
• David S. Baker, Democratic

Other candidates

• Henry B. Metcalf, Prohibition
• Charles G. Baylor, Socialist Labor
• Henry A. Burlingame, People's

Results

1894 Rhode Island gubernatorial election^[1]

Party		Candidate	Votes	%	±%
	Republican	Daniel Russell Brown (incumbent)	29,157	53.15%
	Democratic	David S. Baker	22,650	41.29%
	Prohibition	Henry B. Metcalf	2,241	4.09%
	Socialist Labor	Charles G. Baylor	592	1.08%
	Populist	Henry A. Burlingame	223	0.41%
Majority			6,507
Turnout
	Republican hold		Swing