1888 United States presidential election in Massachusetts

Main article: 1888 United States presidential election

The 1888 United States presidential election in Massachusetts took place on November 6, 1888, as part of the 1888 United States presidential election. Voters chose 14 representatives, or electors to the Electoral College, who voted for president and vice president.

1888 United States presidential election in Massachusetts

← 1884 November 6, 1888 1892 →
Turnout	71.7%[1] 2.4 pp
Nominee Benjamin Harrison Grover Cleveland Party Republican Democratic Home state Indiana New York Running mate Levi P. Morton Allen G. Thurman Electoral vote 14 0 Popular vote 183,892 151,590 Percentage 53.42% 44.04%
County Results Municipality Results Harrison   40–50%   50–60%   60–70%   70–80%   80–90%   90–100% Cleveland   40–50%   50–60%   60–70%   70–80% Tie   40–50%
President before election Grover Cleveland Democratic Elected President Benjamin Harrison Republican

Massachusetts voted for the Republican nominee, Benjamin Harrison, over the Democratic nominee, incumbent President Grover Cleveland. Harrison won the state by a margin of 9.38%.

Results

1888 United States presidential election in Massachusetts[2]
Party		Candidate	Running mate	Popular vote		Electoral vote
				Count	%	Count	%
	Republican	Benjamin Harrison of Indiana	Levi Parsons Morton of New York	183,892	53.42%	14	100.00%
	Democratic	Grover Cleveland of New York (incumbent)	Allen Granberry Thurman of Ohio	151,590	44.04%	0	0.00%
	Prohibition	Clinton Bowen Fisk of New Jersey	John Anderson Brooks of Missouri	8,701	2.53%	0	0.00%
	N/A	Others	Others	60	0.02%	0	0.00%
Total				344,243	100.00%	14	100.00%

See also

• United States presidential elections in Massachusetts

References

1. Bicentennial Edition: Historical Statistics of the United States, Colonial Times to 1970, part 2, p. 1072.
2. "1888 Presidential General Election Results - Massachusetts". U.S. Election Atlas. Retrieved December 23, 2013.