1880 United States presidential election in Minnesota

Main article: 1880 United States presidential election

The 1880 United States presidential election in Minnesota took place on November 2, 1880, as part of the 1880 United States presidential election. Voters chose five representatives, or electors to the Electoral College, who voted for president and vice president.

1880 United States presidential election in Minnesota

← 1876 November 2, 1880 1884 →

Nominee James A. Garfield Winfield S. Hancock Party Republican Democratic Home state Ohio Pennsylvania Running mate Chester A. Arthur William H. English Electoral vote 5 0 Popular vote 93,902 53,315 Percentage 62.28% 35.36%

County Results Garfield   50-60%   60-70%   70-80%   80-90%   90-100% Hancock   50-60%   60-70%

President before election Rutherford B. Hayes Republican Elected President James A. Garfield Republican

Minnesota voted for the Republican nominee, James A. Garfield, over the Democratic nominee, Winfield Scott Hancock. Garfield won the state by a margin of 26.92%.

With 62.28% of the popular vote, Minnesota would be Garfield's third strongest victory in terms of percentage in the popular vote after Vermont and Nebraska.^[1]

Results

1880 United States presidential election in Minnesota[2]
Party		Candidate	Running mate	Popular vote		Electoral vote
				Count	%	Count	%
	Republican	James Abram Garfield of Ohio	Chester Alan Arthur of New York	93,902	62.87%	3	100.00%
	Democratic	Winfield Scott Hancock of Pennsylvania	William Hayden English of Indiana	53,315	35.36%	0	0.00%
	Greenback	James Baird Weaver of Iowa	Barzillai Jefferson Chambers of Texas	3,267	2.17%	0	0.00%
	Prohibition	Neal Dow of Maine	Henry Adams Thompson of Ohio	286	0.19%	0	0.00%
Total				150,770	100.00%	5	100.00%

See also

• United States presidential elections in Minnesota

References

1. "1880 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.
2. "1880 Presidential General Election Results - Minnesota".