1880 United States presidential election in Massachusetts

Main article: 1880 United States presidential election

The 1880 United States presidential election in Massachusetts took place on November 2, 1880, as part of the 1880 United States presidential election. Voters chose 13 representatives, or electors to the Electoral College, who voted for president and vice president.

1880 United States presidential election in Massachusetts

← 1876 November 2, 1880 1884 →
Turnout	71.2%[1] 1.1 pp
Nominee James A. Garfield Winfield S. Hancock Party Republican Democratic Home state Ohio Pennsylvania Running mate Chester A. Arthur William H. English Electoral vote 13 0 Popular vote 165,198 111,720 Percentage 58.53% 39.58%
County Results Municipality results Garfield   40-50%   50-60%   60-70%   70-80%   80-90%   90-100% Hancock   40-50%   50-60%   60-70% Other   No Vote
President before election Rutherford B. Hayes Republican Elected President James A. Garfield Republican

Massachusetts voted for the Republican nominee, James A. Garfield, over the Democratic nominee, Winfield Scott Hancock. Garfield won the state by a margin of 18.95%.

Results

1880 United States presidential election in Massachusetts[2]
Party		Candidate	Running mate	Popular vote		Electoral vote
				Count	%	Count	%
	Republican	James Abram Garfield of Ohio	Chester Alan Arthur of New York	165,198	58.53%	13	100.00%
	Democratic	Winfield Scott Hancock of Pennsylvania	William Hayden English of Indiana	111,720	39.58%	0	0.00%
	Greenback	James Baird Weaver of Iowa	Barzillai Jefferson Chambers of Texas	4,548	1.61%	0	0.00%
	Prohibition	Neal Dow of Maine	Henry Adams Thompson of Ohio	682	0.24%	0	0.00%
	N/A	Others	Others	117	0.04%	0	0.00%
Total				282,265	100.00%	13	100.00%

See also

• United States presidential elections in Massachusetts

References

1. Bicentennial Edition: Historical Statistics of the United States, Colonial Times to 1970, part 2, p. 1072.
2. "1880 Presidential General Election Results - Massachusetts".