1880 United States presidential election in Indiana

Main article: 1880 United States presidential election

The 1880 United States presidential election in Indiana took place on November 2, 1880, as part of the 1880 United States presidential election. Voters chose 15 representatives, or electors to the Electoral College, who voted for president and vice president.

1880 United States presidential election in Indiana

← 1876 November 2, 1880 1884 →

Nominee James A. Garfield Winfield S. Hancock Party Republican Democratic Home state Ohio Pennsylvania Running mate Chester A. Arthur William H. English Electoral vote 15 0 Popular vote 232,164 225,522 Percentage 49.33% 47.91%

County Results Garfield   40-50%   50-60%   60-70% Hancock   40-50%   50-60%   60-70%   70-80% Tie   <50%

President before election Rutherford B. Hayes Republican Elected President James A. Garfield Republican

Indiana voted for the Republican nominee, James A. Garfield, over the Democratic nominee, Winfield Scott Hancock. Garfield won the state by a narrow margin of 1.42%.

Results

1880 United States presidential election in Indiana[1]
Party		Candidate	Running mate	Popular vote		Electoral vote
				Count	%	Count	%
	Republican	James Abram Garfield of Ohio	Chester Alan Arthur of New York	232,164	49.33%	15	100.00%
	Democratic	Winfield Scott Hancock of Pennsylvania	William Hayden English of Indiana	225,522	47.91%	0	0.00%
	Greenback	James Baird Weaver of Iowa	Barzillai Jefferson Chambers of Texas	12,986	2.76%	0	0.00%
Total				470,672	100.00%	15	100.00%

See also

• United States presidential elections in Indiana

Notes

References

1. "1880 Presidential General Election Results - Indiana".