1872 United States presidential election in New Jersey

Main article: 1872 United States presidential election

The 1872 United States presidential election in New Jersey took place on November 5, 1872. All contemporary 37 states were part of the 1872 United States presidential election. The state voters chose nine electors to the Electoral College, which selected the president and vice president.

1872 United States presidential election in New Jersey

← 1868 November 5, 1872 1876 →

Nominee Ulysses S. Grant Horace Greeley Party Republican Liberal Republican Home state Illinois New York Running mate Henry Wilson Benjamin G. Brown Electoral vote 9 0 Popular vote 91,656 76,456 Percentage 54.52% 45.48%

County Results Grant   50-60%   60-70% Greeley   50-60%

President before election Ulysses S. Grant Republican Elected President Ulysses S. Grant Republican

New Jersey was won by the Republican nominees, incumbent President Ulysses S. Grant of Illinois and his running mate Senator Henry Wilson of Massachusetts. Grant and Wilson defeated the Liberal Republican and Democratic nominees, former Congressman Horace Greeley of New York and his running mate former Senator and Governor Benjamin Gratz Brown of Missouri by a margin of 9.04%.

This was the first time the Republicans won all the electoral votes of New Jersey, (see 1860 election in New Jersey for more information) as well as the popular vote. They would not win either again until 1896, 24 years later.

Results

1872 United States presidential election in New Jersey[1]
Party		Candidate	Running mate	Popular vote		Electoral vote
				Count	%	Count	%
	Republican	Ulysses S. Grant of Illinois	Henry Wilson of Massachusetts	91,656	54.52%	9	100.00%
	Liberal Republican	Horace Greeley of New York	Benjamin Gratz Brown of Missouri	76,456	45.48%	0	0.00%
Total				168,112	100.00%	9	100.00%

See also

• United States presidential elections in New Jersey

References

1. "1872 Presidential General Election Results - New Jersey".