1864 United States presidential election in New York

Main article: 1864 United States presidential election

The 1864 United States presidential election in New York took place on November 8, 1864, as part of the 1864 United States presidential election. Voters chose 33 representatives, or electors to the Electoral College, who voted for president and vice president.

1864 United States presidential election in New York

← 1860 November 8, 1864 1868 →
Turnout	89.3%[1] 6.2 pp
Nominee Abraham Lincoln George B. McClellan Party National Union Democratic Home state Illinois New Jersey Running mate Andrew Johnson George H. Pendleton Electoral vote 33 0 Popular vote 368,735 361,986 Percentage 50.46% 49.54%
County Results Lincoln   50–60%   60–70%   70–80% McClellan   50–60%   60–70%
President before election Abraham Lincoln Republican Elected President Abraham Lincoln National Union

New York voted for the National Union candidate, incumbent Republican president Abraham Lincoln and his running mate Andrew Johnson. They defeated the Democratic candidate George B. McClellan and his running mate George H. Pendleton. Lincoln won the state by a bare margin of 0.92%.

Although he lost the state, New York would prove to be McClellan's fourth strongest state after Kentucky, New Jersey, and Delaware.^[2]

Results

1864 United States presidential election in New York[3]
Party		Candidate	Votes	Percentage	Electoral votes
	National Union	Abraham Lincoln (incumbent)	368,735	50.46%	33
	Democratic	George B. McClellan	361,986	49.54%	0
Totals			730,721	100.0%	33

See also

• United States presidential elections in New York

References

1. Bicentennial Edition: Historical Statistics of the United States, Colonial Times to 1970, part 2, p. 1072.
2. "1864 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.
3. "1864 Presidential General Election Results - New York".