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1852 United States presidential election in New York
From Wikipedia, the free encyclopedia
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The 1852 United States presidential election in New York took place on November 2, 1852, as part of the 1852 United States presidential election. Voters chose 35 representatives, or electors to the Electoral College, who voted for president and vice president.
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New York voted for the Democratic candidate, Franklin Pierce, over the Whig Party candidate, Winfield Scott. Pierce won the state by a margin of 5.21%. Abolitionist Free Soil party candidate John Hale took 4.85% of the vote. William Goodell of the Liberty party, another smaller abolitionist party, also took a tiny portion of the vote. So did Daniel Webster, running as a Whig nominated against his will by a group of southern Whigs unsatisfied with Scott. Despite dying nine days before the election, he received 0.08% of the vote, mostly in New York City. This was one of the few northern states where he received votes.[2]
This was the last time a Democrat won the state outside of New York City proper until 1912 and the last until 1964, when Lyndon Johnson swept every New York county, that they received a majority. It was thus the last time until 1964 that many New York Counties voted for a Democrat, namely Allegany, Broome, Chenango, Delaware, Jefferson, Madison, Onondaga, Oswego, St. Lawrence, Tioga, Warren, and Wayne counties.
This was the last election in which the Whigs and not the Republican Party provided the main opposition to the Democrats. After the birth of the Republican Party, upstate New York remained a Republican bastion up until the 1990s.[3]
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Results
Results by county
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See also
References
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