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The 1845 Virginia gubernatorial election was held on 10 December 1845 in order to elect the Governor of Virginia. Democratic nominee and former U.S. House representative William Smith defeated John Brockenbrough and 15 other candidates.
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On 10 December 1845, the Virginian General Assembly began voting for governor. William Smith, who had previously been selected by a caucus to be Democratic nominee,[1] was nominated alongside John Brockenbrough and 14 other candidates. Smith won a majority of the votes and was sworn in as governor on 1 January 1846.[2][3]
| Senate ballot[2] | |||||||||||
|---|---|---|---|---|---|---|---|---|---|---|---|
| Party | Candidate | Votes | % | ||||||||
| Democratic | William Smith | 20 | 66.67 | ||||||||
| John Brockenbrough | 6 | 20.00 | |||||||||
| Four others one each | 4 | 13.33 | |||||||||
| Valid votes | 30 | 100 | |||||||||
| Total | 30 | 100 | |||||||||
| House of Delegates ballot[3] | |||||||||||
|---|---|---|---|---|---|---|---|---|---|---|---|
| Party | Candidate | Votes | % | ||||||||
| Democratic | William Smith | 74 | 56.92 | ||||||||
| John Brockenbrough | 34 | 26.15 | |||||||||
| Valentine W. Southall | 11 | 8.46 | |||||||||
| William Cabell Rives | 2 | 1.54 | |||||||||
| Andrew Stevenson | 2 | 1.54 | |||||||||
| Seven others one each | 7 | 5.38 | |||||||||
| Valid votes | 130 | 100 | |||||||||
| Total | 130 | 100 | |||||||||
| Joint total[2][3] | |||||||||||
|---|---|---|---|---|---|---|---|---|---|---|---|
| Party | Candidate | Votes | % | ||||||||
| Democratic | William Smith | 94 | 58.75 | ||||||||
| John Brockenbrough | 40 | 25.00 | |||||||||
| Valentine W. Southall | 11 | 6.88 | |||||||||
| James Lyons | 2 | 1.25 | |||||||||
| William Cabell Rives | 2 | 1.25 | |||||||||
| Andrew Stevenson | 2 | 1.25 | |||||||||
| 9 others one each | 9 | 5.63 | |||||||||
| Valid votes | 160 | 100 | |||||||||
| Total | 160 | 100 | |||||||||
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