1844 United States presidential election in Pennsylvania

Main article: 1844 United States presidential election

The 1844 United States presidential election in Pennsylvania took place between November 1 and December 4, 1844, as part of the 1844 United States presidential election. Voters chose 26 representatives, or electors to the Electoral College, who voted for President and Vice President.

1844 United States presidential election in Pennsylvania

← 1840 November 1 – December 4, 1844 1848 →

Nominee James K. Polk Henry Clay Party Democratic Whig Home state Tennessee Kentucky Running mate George M. Dallas Theodore Frelinghuysen Electoral vote 26 0 Popular vote 167,447 161,125 Percentage 50.50% 48.59%

County Results Polk   40–50%   50–60%   60–70%   80–90% Clay   50–60%   60–70%   70–80%

President before election John Tyler Independent Elected President James K. Polk Democratic

Pennsylvania voted for the Democratic candidate, James K. Polk, over the Whig candidate, Henry Clay. Polk won Pennsylvania by a narrow margin of 1.91%.

Results

1844 United States presidential election in Pennsylvania[1]
Party		Candidate	Votes	Percentage	Electoral votes
	Democratic	James K. Polk	167,447	50.50%	26
	Whig	Henry Clay	161,125	48.59%	0
	Liberty	James G. Birney	3,000	0.90%	0
Totals			331,572	100.0%	26

See also

• List of United States presidential elections in Pennsylvania

References

1. "1844 Presidential General Election Results - Pennsylvania". U.S. Election Atlas. Retrieved August 4, 2012.