1828 United States presidential election in Massachusetts
From Wikipedia, the free encyclopedia
From Wikipedia, the free encyclopedia
The 1828 United States presidential election in Massachusetts took place between October 31 and December 2, 1828, as part of the 1828 United States presidential election. Voters chose 15 representatives, or electors to the Electoral College, who voted for President and Vice President.
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| Turnout | 25.7%[1]  3.3 pp | |||||||||||||||||||||||||
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County Results
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Massachusetts voted for the National Republican candidate, incumbent president John Quincy Adams, over the Democratic candidate, Andrew Jackson. Adams won Massachusetts by a landslide margin of 60.97%.
With 76.36% of the popular vote, Adams' home state would prove to be his second strongest victory in the 1828 election after neighboring Rhode Island.[2]
| 1828 United States presidential election in Massachusetts[3] | |||||
|---|---|---|---|---|---|
| Party | Candidate | Votes | Percentage | Electoral votes | |
| National Republican | John Quincy Adams (incumbent) | 29,836 | 76.36% | 15 | |
| Democratic | Andrew Jackson | 6,012 | 15.39% | 0 | |
| N/A | Other | 3,226 | 8.26% | 0 | |
| Totals | 39,074 | 100.0% | 15 | ||
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