1824 United States presidential election in Pennsylvania

Main article: 1824 United States presidential election

The 1824 United States presidential election in Pennsylvania took place between October 26 and December 2, 1824, as part of the 1824 United States presidential election. Voters chose 28 representatives, or electors to the Electoral College, who voted for President and Vice President.

1824 United States presidential election in Pennsylvania

← 1820 October 26 – December 2, 1824 1828 →

Nominee Andrew Jackson John Quincy Adams William H. Crawford Party Democratic-Republican Democratic-Republican Democratic-Republican Home state Tennessee Massachusetts Georgia Running mate John C. Calhoun John C. Calhoun Nathaniel Macon Electoral vote 28 0 0 Popular vote 35,929 5,436 4,182 Percentage 76.04% 11.50% 8.85%

County Results Jackson   50-60%   60-70%   70-80%   80-90%   90-100%

President before election James Monroe Democratic-Republican Elected President John Quincy Adams Democratic-Republican

During this election, the Democratic-Republican Party was the only major national party, and 4 different candidates from this party sought the Presidency. Pennsylvania voted for Andrew Jackson over John Quincy Adams, William H. Crawford, and Henry Clay. Jackson won Pennsylvania by a wide margin of 64.54%.

This is the only time any presidential candidate has swept every Pennsylvania county.

Results

1824 United States presidential election in Pennsylvania[1]
Party		Candidate	Votes	Percentage	Electoral votes
	Democratic-Republican	Andrew Jackson	35,929	76.04%	28
	Democratic-Republican	John Quincy Adams	5,436	11.50%	0
	Democratic-Republican	William H. Crawford	4,182	8.85%	0
	Democratic-Republican	Henry Clay	1,705	3.61%	0
Totals			47,252	100.0%	28

See also

• List of United States presidential elections in Pennsylvania

References

1. "1824 Presidential General Election Results - Pennsylvania". U.S. Election Atlas. Retrieved August 4, 2012.