1824 United States presidential election in North Carolina

Main article: 1824 United States presidential election

The 1824 United States presidential election in North Carolina took place between October 26 and December 2, 1824, as part of the 1824 United States presidential election. Voters chose 15 representatives, or electors to the Electoral College, who voted for President and Vice President.

1824 United States presidential election in North Carolina

← 1820 October 26 – December 2, 1824 1828 →

Nominee Andrew Jackson William H. Crawford Party Democratic-Republican Democratic-Republican Home state Tennessee Georgia Running mate John C. Calhoun Nathaniel Macon Electoral vote 15 0 Popular vote 20,231 15,622 Percentage 56.03% 43.26%

County Results Jackson   50-60%   60-70%   70-80%   80-90%   90-100% Crawford   50-60%   60-70%   70-80%   80-90%   90-100%

President before election James Monroe Democratic-Republican Elected President John Quincy Adams Democratic-Republican

During this election, the Democratic-Republican Party was the only major national party, and four different candidates from this party sought the Presidency. North Carolina voted for Andrew Jackson over William H. Crawford, Henry Clay, and John Quincy Adams. Jackson won North Carolina by a margin of 12.77%.

Results

1824 United States presidential election in North Carolina[1]
Party		Candidate	Votes	Percentage	Electoral votes
	Democratic-Republican	Andrew Jackson	20,231	56.03%	15
	Democratic-Republican	William H. Crawford	15,622	43.26%	0
	N/A	Others	256	0.71%	0
Totals			36,109	100.0%	15

References

1. "1824 Presidential General Election Results - North Carolina". U.S. Election Atlas. Retrieved February 27, 2013.