1817 Georgia gubernatorial election

The 1817 Georgia gubernatorial election was held on 10 November 1817 in order to elect the Governor of Georgia. Democratic-Republican candidate and incumbent acting Governor William Rabun defeated fellow Democratic-Republican candidate John Clark in a Georgia General Assembly vote.^[1]

1817 Georgia gubernatorial election

← 1815 10 November 1817 1819 →

Nominee William Rabun John Clark Party Democratic-Republican Democratic-Republican Popular vote 62 57 Percentage 52.10% 47.90%

Governor before election William Rabun (Acting) Democratic-Republican Elected Governor William Rabun Democratic-Republican

General election

On election day, 10 November 1817, Democratic-Republican candidate William Rabun won the election against his opponent fellow Democratic-Republican candidate John Clark. Rabun was officially sworn in as the 29th Governor of Georgia on 10 November 1817.^[2]

Results

Georgia gubernatorial election, 1817^[3]

Party		Candidate	Votes	%
	Democratic-Republican	William Rabun	62	52.10
	Democratic-Republican	John Clark	57	47.90
Total votes			119	100.00
	Democratic-Republican hold

References

1. "Georgia 1817 Governor". Tufts Digital Collations and Archives. A New Nation Votes: American Election Returns 1787–1825. Tufts University. Retrieved 8 December 2023.
2. "GA Governor". ourcampaigns.com. 18 July 2022. Retrieved 8 December 2023.
3. Dubin, Michael J. (2003). United States Gubernatorial Elections, 1776-1860: The Official Results by State and County. Jefferson: McFarland & Company. ISBN 9780786414390.