Wakulla County, Florida
County in Florida, United States / From Wikipedia, the free encyclopedia
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Wakulla County is a county located in the Big Bend region in the northern portion of the U.S. state of Florida. As of the 2020 census, the population was 33,764. Its county seat is Crawfordville.[1]
Quick Facts Country, State ...
Wakulla County | |
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Coordinates: 30°09′N 84°23′W | |
Country | United States |
State | Florida |
Founded | March 11, 1843 |
Named for | Wakulla River |
Seat | Crawfordville |
Largest city | Sopchoppy |
Area | |
• Total | 736 sq mi (1,910 km2) |
• Land | 606 sq mi (1,570 km2) |
• Water | 129 sq mi (330 km2) 17.6% |
Population (2020) | |
• Total | 33,764 |
• Density | 55/sq mi (21/km2) |
Time zone | UTC−5 (Eastern) |
• Summer (DST) | UTC−4 (EDT) |
Congressional district | 2nd |
Website | www |
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Wakulla County is part of the Tallahassee, Florida Metropolitan Statistical Area.
Wakulla County has a near-absence of any municipal population, with two small municipalities holding about 3% of the population. The county seat, Crawfordville, is one of only two unincorporated county seats among Florida's 67 counties.