Shueyville, Iowa
City in Iowa, United States / From Wikipedia, the free encyclopedia
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Shueyville is a city in Johnson County, Iowa, United States. It is part of the Iowa City, Iowa Metropolitan Statistical Area. The population was 731 at the time of the 2020 census.[2]
Quick Facts Country, State ...
Shueyville, Iowa | |
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Coordinates: 41°50′53″N 91°38′55″W | |
Country | United States |
State | Iowa |
County | Johnson |
Area | |
• Total | 1.86 sq mi (4.83 km2) |
• Land | 1.86 sq mi (4.83 km2) |
• Water | 0.00 sq mi (0.00 km2) |
Elevation | 801 ft (244 m) |
Population (2020) | |
• Total | 731 |
• Density | 392.17/sq mi (151.45/km2) |
Time zone | UTC-6 (Central (CST)) |
• Summer (DST) | UTC-5 (CDT) |
FIPS code | 19-72840 |
GNIS feature ID | 0461591 |
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