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Seward, New York
Town in New York, United States / From Wikipedia, the free encyclopedia
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Seward is a town in Schoharie County, New York, United States. The population was 1,583 at the 2020 census.[2] The town is named after senator, governor, and secretary of state William H. Seward.
Quick Facts Country, State ...
Seward, New York | |
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![]() Location in Schoharie County and the state of New York. | |
Coordinates: 42°42′26″N 74°34′58″W | |
Country | United States |
State | New York |
County | Schoharie |
Area | |
• Total | 36.46 sq mi (94.42 km2) |
• Land | 36.38 sq mi (94.22 km2) |
• Water | 0.08 sq mi (0.21 km2) |
Elevation | 1,158 ft (353 m) |
Population (2020) | |
• Total | 1,583 |
Time zone | UTC-5 (Eastern (EST)) |
• Summer (DST) | UTC-4 (EDT) |
ZIP code | 12043 |
Area code | 518 |
FIPS code | 36-66542 |
GNIS feature ID | 0979483 |
Website | Town website |
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The Town of Seward is in the northwestern part of the county and is northeast of Oneonta.