Semenov-Tian-Shansky Peak

For the mountain on the border between Kazakhstan and Kyrgyzstan, see Semyonov Peak.

Semenov-Tian-Shansky Peak (Russian: Пик Семёнова-Тяньшанского, romanized: Pik Semonova-Tyan'shanskogo, Kyrgyz: Аламүдүн чокусу, romanized: Alamüdün çokusu, lit. 'Alamedin Peak') is a mountain in the Kyrgyz Ala-Too Range of the Tian Shan. It is located in Ala Archa National Park in Kyrgyzstan. It is the tallest mountain in the Kyrgyz Ala-Too Range and is an Ultra with a prominence of 2231m.^[1]

Semenov-Tian-Shansky Peak
Pik Semonova-Tyan'shanskogo, Alamedin Peak
The view from Uchitel Peak in the northwest
Highest point
Elevation	4,895 m (16,060 ft)
Prominence	2,231 m (7,320 ft)
Isolation	233.57 km (145.13 mi)
Coordinates	42°31′16″N 74°34′18″E
Geography
Semenov-Tian-Shansky Peak Kyrgyzstan
Parent range	Kyrgyz Ala-Too Range, Tian Shan

The mountain is situated between the Ala-Archa River to the west and the Alamedin River to the east.

History

The peak is named for the Russian geographer Peter Semenov-Tian-Shansky.

References

1. "Ala Archa National Park".