Roxbury, New York
Town in New York, United States / From Wikipedia, the free encyclopedia
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Roxbury is a town in Delaware County, New York, United States. The population was 2,247 at the 2020 census.[2] The town is at the eastern end of the county.
For the community in Queens, see Roxbury, Queens.
Quick Facts Country, State ...
Roxbury, New York | |
---|---|
Coordinates: 42°18′02″N 74°33′11″W | |
Country | United States |
State | New York |
County | Delaware |
Government | |
• Type | Town Council |
• Town Supervisor | Thomas S. Hynes (D) |
• Town Council | |
Area | |
• Total | 87.60 sq mi (226.89 km2) |
• Land | 87.11 sq mi (225.62 km2) |
• Water | 0.49 sq mi (1.27 km2) |
Elevation | 1,506 ft (459 m) |
Population | |
• Total | 2,247 |
• Density | 26/sq mi (9.9/km2) |
Time zone | UTC-5 (Eastern (EST)) |
• Summer (DST) | UTC-4 (EDT) |
ZIP code | 12474 |
Area code | 607 |
FIPS code | 36-025-64001 |
GNIS feature ID | 0979438 |
Website | roxburyny |
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