Palmyra, Utah
CDP in Utah, United States / From Wikipedia, the free encyclopedia
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Palmyra is a census-designated place (CDP) in Utah County, Utah, United States. It is part of the Provo–Orem Metropolitan Statistical Area. The population was 491 at the 2010 census.[3] Palmyra is located directly west of Springville and northwest of Spanish Fork.
Quick Facts Country, State ...
Palmyra, Utah | |
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Coordinates: 40°7′36″N 111°41′7″W | |
Country | United States |
State | Utah |
County | Utah |
Named for | Palmyra, New York |
Area | |
• Total | 11.7 sq mi (30.4 km2) |
• Land | 11.5 sq mi (29.8 km2) |
• Water | 0.2 sq mi (0.6 km2) |
Elevation | 4,524 ft (1,379 m) |
Population (2010) | |
• Total | 491 |
• Density | 42/sq mi (16/km2) |
Time zone | UTC-7 (Mountain (MST)) |
• Summer (DST) | UTC-6 (MDT) |
ZIP code | 84660 |
Area code | 801 |
FIPS code | 49-57630[1] |
GNIS feature ID | 1444167[2] |
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Palmyra was first settled in 1852.