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Commune in Bourgogne-Franche-Comté, France From Wikipedia, the free encyclopedia
Montmahoux (French pronunciation: [mɔ̃ma.u]) is a commune in the Doubs department in the Bourgogne-Franche-Comté region in eastern France.
Montmahoux | |
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![]() An aerial view of Montmahoux | |
Coordinates: 46°59′03″N 6°02′06″E | |
Country | France |
Region | Bourgogne-Franche-Comté |
Department | Doubs |
Arrondissement | Besançon |
Canton | Ornans |
Intercommunality | Loue-Lison |
Government | |
• Mayor (2020–2026) | Vincent Marguet[1] |
Area 1 | 6.52 km2 (2.52 sq mi) |
Population (2021)[2] | 91 |
• Density | 14/km2 (36/sq mi) |
Time zone | UTC+01:00 (CET) |
• Summer (DST) | UTC+02:00 (CEST) |
INSEE/Postal code | 25404 /25270 |
Elevation | 550–823 m (1,804–2,700 ft) |
1 French Land Register data, which excludes lakes, ponds, glaciers > 1 km2 (0.386 sq mi or 247 acres) and river estuaries. |
Montmahoux lies 8 km (5.0 mi) south of Amancey on the edge of the gorge of the Boz.
Year | Pop. | ±% |
---|---|---|
1962 | 90 | — |
1968 | 106 | +17.8% |
1975 | 95 | −10.4% |
1982 | 76 | −20.0% |
1990 | 80 | +5.3% |
1999 | 67 | −16.2% |
2008 | 80 | +19.4% |
2012 | 105 | +31.2% |