Lake Alfred, Florida
City in Florida, United States of America / From Wikipedia, the free encyclopedia
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Lake Alfred is a city in Polk County, Florida, United States. It is part of the Lakeland–Winter Haven Metropolitan Statistical Area. The population was approximately 6,374 at the 2020 US census.
Quick Facts Country, State ...
Lake Alfred, Florida | |
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City of Lake Alfred | |
Coordinates: 28°06′15″N 81°43′35″W | |
Country | United States of America |
State | Florida |
County | Polk |
Incorporated | 1915[1] |
Government | |
• Mayor | Nancy Z. Daley |
• Vice Mayor | Mac Fuller |
• Commissioners | Jack Dearmin, Brent Eden, and Charles Lake |
• City Manager | Ryan Leavengood |
• City Clerk | Linda Bourgeois |
Area | |
• Total | 13.10 sq mi (33.93 km2) |
• Land | 9.20 sq mi (23.82 km2) |
• Water | 3.90 sq mi (10.10 km2) |
Elevation | 131 ft (40 m) |
Population (2020) | |
• Total | 6,374 |
• Density | 692.90/sq mi (267.54/km2) |
Time zone | UTC-5 (Eastern (EST)) |
• Summer (DST) | UTC-4 (EDT) |
ZIP code | 33850 |
Area code | 863 |
FIPS code | 12-37525[4] |
GNIS feature ID | 2404856[3] |
Website | mylakealfred |
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