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Township in Indiana, United States From Wikipedia, the free encyclopedia
Jefferson Township is one of six townships in Switzerland County, Indiana, United States. As of the 2020 census, its population was 3,203 and it contained 1,549 housing units.[1]
Jefferson Township | |
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![]() Location in Switzerland County | |
Coordinates: 38°47′47″N 85°03′08″W | |
Country | ![]() |
State | ![]() |
County | Switzerland |
Government | |
• Type | Indiana township |
Area | |
• Total | 37.2 sq mi (96 km2) |
• Land | 36.96 sq mi (95.7 km2) |
• Water | 0.24 sq mi (0.6 km2) 0.65% |
Elevation | 719 ft (219 m) |
Population (2020) | |
• Total | 3,203 |
• Density | 86/sq mi (33/km2) |
ZIP codes | 47011, 47020, 47043 |
GNIS feature ID | 453499 |
According to the 2010 census, the township has a total area of 37.2 square miles (96 km2), of which 36.96 square miles (95.7 km2) (or 99.35%) is land and 0.24 square miles (0.62 km2) (or 0.65%) is water.[3]
(This list is based on USGS data and may include former settlements.)
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