Jefferson, South Dakota
City in South Dakota, United States / From Wikipedia, the free encyclopedia
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Jefferson is a city in Union County, South Dakota, United States. The population was 475 at the 2020 census.[5] It is part of the Sioux City, IA-NE-SD Metropolitan Statistical Area. Jefferson was founded in 1859. Every year the citizens of Jefferson and surrounding area celebrate the founding of Jefferson during "Jefferson Days", a festival that includes a movie in the park, a car show, fireworks and parade.[6]
Quick Facts Country, State ...
Jefferson, South Dakota | |
---|---|
Coordinates: 42°36′15″N 96°33′58″W | |
Country | United States |
State | South Dakota |
County | Union |
Incorporated | 1895[1] |
Area | |
• Total | 0.51 sq mi (1.32 km2) |
• Land | 0.51 sq mi (1.32 km2) |
• Water | 0.00 sq mi (0.00 km2) |
Elevation | 1,116 ft (340 m) |
Population | |
• Total | 475 |
• Density | 931.37/sq mi (359.27/km2) |
Time zone | UTC-6 (Central (CST)) |
• Summer (DST) | UTC-5 (CDT) |
ZIP code | 57038 |
Area code | 605 |
FIPS code | 46-32700 |
GNIS feature ID | 1267441[3] |
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The city has the name of President Thomas Jefferson.[7]