Jefferson, Ohio
Village in Ohio, United States / From Wikipedia, the free encyclopedia
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Not to be confused with Jefferson County, Ohio or Jeffersonville, Ohio.
For the community in Wayne County, see Jefferson, Wayne County, Ohio.
Jefferson is a village in and the county seat of Ashtabula County, Ohio, United States. The population was 3,226 at the 2020 census.[4] It is part of the Ashtabula micropolitan area, 50 miles (80 km) northeast of Cleveland.
Quick Facts Country, State ...
Jefferson, Ohio | |
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Coordinates: 41°44′19″N 80°45′25″W | |
Country | United States |
State | Ohio |
County | Ashtabula |
Area | |
• Total | 2.54 sq mi (6.57 km2) |
• Land | 2.54 sq mi (6.57 km2) |
• Water | 0.00 sq mi (0.00 km2) |
Elevation | 961 ft (293 m) |
Population (2020) | |
• Total | 3,226 |
• Density | 1,271.58/sq mi (491.04/km2) |
Time zone | UTC-5 (Eastern (EST)) |
• Summer (DST) | UTC-4 (EDT) |
ZIP code | 44047 |
Area code | 440 |
FIPS code | 39-38500[3] |
GNIS feature ID | 1042061[2] |
Website | http://www.jeffersonohio.us/ |
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Modern-day Jefferson sports the world's only perambulator museum and a historical complex including several restored 19th-century buildings. Joshua Giddings' law office has also been restored as a museum. Annual village events include the Ashtabula County Fair, the Strawberry Festival, Jefferson Days, and the Covered Bridge Festival.