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Chemical compound From Wikipedia, the free encyclopedia
Iridium(III) iodide is an iodide of iridium, with the chemical formula of IrI3.
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Names | |
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Other names
Iridium triiodide | |
Identifiers | |
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Properties | |
I3Ir | |
Molar mass | 572.930 g·mol−1 |
Appearance | dark brown solid[1] |
Density | 7.4 g·cm−3[1] |
Solubility | insoluble in water and benzene[1] |
Related compounds | |
Other anions |
iridium(III) hydroxide iridium(III) chloride Iridium(III) bromide |
Other cations |
Rhodium(III) iodide |
Related compounds |
Iridium(IV) iodide |
Except where otherwise noted, data are given for materials in their standard state (at 25 °C [77 °F], 100 kPa).
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Iridium(III) iodide can be obtained by reducing iridium(IV) iodide with hydrogen at 210 °C.[2] It can also be formed by the reaction of iridium dioxide[3] or iridium(III) hydroxide with hydrogen iodide.[4]
Iridium(III) iodide is a dark brown solid that is insoluble in water.[1] It is monoclinic like chromium trichloride.[5][6] Its trihydrate is yellow and can be dehydrated into the dihydrate or anhydrous form on heating. Iridium(III) iodide also has a monohydrate.[3][7]
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