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Hayesville, Iowa
City in Iowa, United States / From Wikipedia, the free encyclopedia
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Hayesville is a city in Keokuk County, Iowa, United States. The population was 41 at the time of the 2020 census.[3]
Quick Facts Country, State ...
Hayesville, Iowa | |
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![]() Location of Hayesville, Iowa | |
Coordinates: 41°15′53″N 92°14′56″W | |
Country | ![]() |
State | ![]() |
County | Keokuk |
Area | |
• Total | 0.25 sq mi (0.65 km2) |
• Land | 0.25 sq mi (0.65 km2) |
• Water | 0.00 sq mi (0.00 km2) |
Elevation | 794 ft (242 m) |
Population (2020) | |
• Total | 41 |
• Density | 164.00/sq mi (63.31/km2) |
Time zone | UTC-6 (Central (CST)) |
• Summer (DST) | UTC-5 (CDT) |
ZIP code | 52562 |
Area code | 641 |
FIPS code | 19-35445 |
GNIS feature ID | 2394333[2] |
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