Corfu, New York
Village in New York, United States / From Wikipedia, the free encyclopedia
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For other uses, see Corfu (disambiguation).
Corfu is a village in Genesee County, New York, United States. The population was 709 at the 2010 census.[2] It is named after the Greek island of Corfu.[3]
Quick Facts Country, State ...
Corfu, New York | |
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Coordinates: 42°57′31″N 78°24′14″W | |
Country | United States |
State | New York |
County | Genesee |
Town | Pembroke |
Area | |
• Total | 0.99 sq mi (2.58 km2) |
• Land | 0.99 sq mi (2.58 km2) |
• Water | 0.00 sq mi (0.00 km2) |
Elevation | 863 ft (263 m) |
Population (2020) | |
• Total | 689 |
• Density | 692.46/sq mi (267.33/km2) |
Time zone | UTC-5 (Eastern (EST)) |
• Summer (DST) | UTC-4 (EDT) |
ZIP code | 14036 |
Area code | 585 |
FIPS code | 36-18201 |
GNIS feature ID | 0947446 |
Website | www |
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The village of Corfu lies along the southern edge of the town of Pembroke; about 1.5 acres (0.6 ha) within the village limits are within the town of Darien to the south.[4]